A potential difference of 10 volts is maintained across a resistance of 30 ohms. How much current results, and how much power is required to maintain this current?
A greater resistance implies a lesser current, while a greater voltage implies a greater current.
By definition of an ohm a circuit has a resistance of 1 ohm if a 1 volt potential difference results in a current of 1 ampere.
Thus the 10 volt potential difference and the 30 ohm resistance result in a current of I = 10 volts / ( 30 ohms) = .3333 volts/ohm = .3333 amperes, or .3333 C/s.
A current of .3333 C/s through a potential difference of 10 volts results in ( .3333 C/s)( 10 J/C) = 3.333 J/s = 3.333 watts.
An ohm is the unit of resistance which permits 1 ampere of current to flow in response to a 1 volt potential difference.
- greater length implies proportionally less potential gradient for a given voltage and hence proportionally less current; greater area implies proportionally more available charge carriers per unit of length and hence proportionally more current.
The figure below charts the relationships among voltage, resistance, current and power.
- Greater voltage or less resistance implies greater current, expressed as I = V / R; resistance is the ratio of voltage to current, expressed as R = V / I; a current I through a resistance R requires a greater voltage drop for a greater current and for a greater resistance, expressed as V = I * R.
- Current is measured in C / s, voltage in J / C, so the product of current and voltage is the number of J / s, or watts, of power.
The relationship P = I * V can be combined with either I = V / R or with V = I * R to yield either P = I * (I * R) = I^2 * R or P = (V / R ) * V = V^2 / R.
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